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7/2(x+12)=5/2(20+x)
We move all terms to the left:
7/2(x+12)-(5/2(20+x))=0
Domain of the equation: 2(x+12)!=0
x∈R
Domain of the equation: 2(20+x))!=0We add all the numbers together, and all the variables
x∈R
7/2(x+12)-(5/2(x+20))=0
We calculate fractions
(14xx/(2(x+12)*2(x+20)))+(-10xx/(2(x+12)*2(x+20)))=0
We calculate terms in parentheses: +(14xx/(2(x+12)*2(x+20))), so:
14xx/(2(x+12)*2(x+20))
We multiply all the terms by the denominator
14xx
Back to the equation:
+(14xx)
We calculate terms in parentheses: +(-10xx/(2(x+12)*2(x+20))), so:We get rid of parentheses
-10xx/(2(x+12)*2(x+20))
We multiply all the terms by the denominator
-10xx
Back to the equation:
+(-10xx)
14xx-10xx=0
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