7/2x+1/2x=3x3/2+5/2x

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Solution for 7/2x+1/2x=3x3/2+5/2x equation: 


x in (-oo:+oo)

(7/2)*x+(1/2)*x = (3*x^3)/2+(5/2)*x // - (3*x^3)/2+(5/2)*x

(7/2)*x-((3*x^3)/2)+(1/2)*x-((5/2)*x) = 0

(-3/2)*x^3+(7/2)*x+(1/2)*x+(-5/2)*x = 0

3/2*x-3/2*x^3 = 0

3/2*x*(1-x^2) = 0

-1*x^2 = -1 // : -1

x^2 = 1

x^2 = 1 // ^ 1/2

abs(x) = 1

x = 1 or x = -1

(3*x)/2 = 0

3/2*x = 0 // : 3/2

x = 0

x in { 1, -1, 0 }

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