7/2x+10/3x=5

Solution for 7/2x+10/3x=5 equation:

7/2x+10/3x=5

We move all terms to the left:

7/2x+10/3x-(5)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We calculate fractions


21x/6x^2+20x/6x^2-5=0

We multiply all the terms by the denominator


21x+20x-5*6x^2=0

We add all the numbers together, and all the variables

41x-5*6x^2=0

Wy multiply elements

-30x^2+41x=0

a = -30; b = 41; c = 0;
Δ = b2-4ac
Δ = 412-4·(-30)·0
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1681}=41$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(41)-41}{2*-30}=\frac{-82}{-60}
=1+11/30
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(41)+41}{2*-30}=\frac{0}{-60}
=0
$