7/2x-3/5x=1

Solution for 7/2x-3/5x=1 equation:

7/2x-3/5x=1

We move all terms to the left:

7/2x-3/5x-(1)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R


We calculate fractions


35x/10x^2+(-6x)/10x^2-1=0

We multiply all the terms by the denominator


35x+(-6x)-1*10x^2=0

Wy multiply elements

-10x^2+35x+(-6x)=0

We get rid of parentheses

-10x^2+35x-6x=0

We add all the numbers together, and all the variables

-10x^2+29x=0

a = -10; b = 29; c = 0;
Δ = b2-4ac
Δ = 292-4·(-10)·0
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-29}{2*-10}=\frac{-58}{-20}
=2+9/10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+29}{2*-10}=\frac{0}{-20}
=0
$