7/2x-3=4/x+1

Solution for 7/2x-3=4/x+1 equation:

7/2x-3=4/x+1

We move all terms to the left:

7/2x-3-(4/x+1)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: x+1)!=0

x∈R


We get rid of parentheses

7/2x-4/x-1-3=0

We calculate fractions


7x/2x^2+(-8x)/2x^2-1-3=0

We add all the numbers together, and all the variables

7x/2x^2+(-8x)/2x^2-4=0

We multiply all the terms by the denominator


7x+(-8x)-4*2x^2=0

Wy multiply elements

-8x^2+7x+(-8x)=0

We get rid of parentheses

-8x^2+7x-8x=0

We add all the numbers together, and all the variables

-8x^2-1x=0

a = -8; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·(-8)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*-8}=\frac{0}{-16}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*-8}=\frac{2}{-16}
=-1/8
$