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7/2x-5/6x=11
We move all terms to the left:
7/2x-5/6x-(11)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 6x!=0We calculate fractions
x!=0/6
x!=0
x∈R
42x/12x^2+(-10x)/12x^2-11=0
We multiply all the terms by the denominator
42x+(-10x)-11*12x^2=0
Wy multiply elements
-132x^2+42x+(-10x)=0
We get rid of parentheses
-132x^2+42x-10x=0
We add all the numbers together, and all the variables
-132x^2+32x=0
a = -132; b = 32; c = 0;
Δ = b2-4ac
Δ = 322-4·(-132)·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-32}{2*-132}=\frac{-64}{-264} =8/33 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+32}{2*-132}=\frac{0}{-264} =0 $
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