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7/2x-6=7/8x
We move all terms to the left:
7/2x-6-(7/8x)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 8x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
7/2x-(+7/8x)-6=0
We get rid of parentheses
7/2x-7/8x-6=0
We calculate fractions
56x/16x^2+(-14x)/16x^2-6=0
We multiply all the terms by the denominator
56x+(-14x)-6*16x^2=0
Wy multiply elements
-96x^2+56x+(-14x)=0
We get rid of parentheses
-96x^2+56x-14x=0
We add all the numbers together, and all the variables
-96x^2+42x=0
a = -96; b = 42; c = 0;
Δ = b2-4ac
Δ = 422-4·(-96)·0
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-42}{2*-96}=\frac{-84}{-192} =7/16 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+42}{2*-96}=\frac{0}{-192} =0 $
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