7/2x-7/5=4/x+4/1

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Solution for 7/2x-7/5=4/x+4/1 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(7/2)*x-(7/5) = 4/x+4/1 // - 4/x+4/1

(7/2)*x-(4/x)-(7/5)-(4/1) = 0

(7/2)*x-4*x^-1-7/5-4 = 0

7/2*x^1-4*x^-1-27/5*x^0 = 0

(7/2*x^2-27/5*x^1-4*x^0)/(x^1) = 0 // * x^2

x^1*(7/2*x^2-27/5*x^1-4*x^0) = 0

x^1

(7/2)*x^2+(-27/5)*x-4 = 0

(7/2)*x^2+(-27/5)*x-4 = 0

DELTA = (-27/5)^2-(-4*4*(7/2))

DELTA = 2129/25

DELTA > 0

x = ((2129/25)^(1/2)-(-27/5))/(2*(7/2)) or x = (-(-27/5)-(2129/25)^(1/2))/(2*(7/2))

x = ((2129/25)^(1/2)+27/5)/7 or x = (27/5-(2129/25)^(1/2))/7

x in { (27/5-(2129/25)^(1/2))/7, ((2129/25)^(1/2)+27/5)/7} 

x in { (27/5-(2129/25)^(1/2))/7, ((2129/25)^(1/2)+27/5)/7 }

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