7/2x=20;x=

Solution for 7/2x=20;x= equation:

7/2x=20x=

We move all terms to the left:

7/2x-(20x)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We add all the numbers together, and all the variables

-20x+7/2x=0

We multiply all the terms by the denominator


-20x*2x+7=0

Wy multiply elements

-40x^2+7=0

a = -40; b = 0; c = +7;
Δ = b2-4ac
Δ = 02-4·(-40)·7
Δ = 1120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1120}=\sqrt{16*70}=\sqrt{16}*\sqrt{70}=4\sqrt{70}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{70}}{2*-40}=\frac{0-4\sqrt{70}}{-80}
=-\frac{4\sqrt{70}}{-80}
=-\frac{\sqrt{70}}{-20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{70}}{2*-40}=\frac{0+4\sqrt{70}}{-80}
=\frac{4\sqrt{70}}{-80}
=\frac{\sqrt{70}}{-20}
$