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7/3(6x-3)=6/5(10x-15)
We move all terms to the left:
7/3(6x-3)-(6/5(10x-15))=0
Domain of the equation: 3(6x-3)!=0
x∈R
Domain of the equation: 5(10x-15))!=0We calculate fractions
x∈R
(35x1/(3(6x-3)*5(10x-15)))+(-18x6/(3(6x-3)*5(10x-15)))=0
We calculate terms in parentheses: +(35x1/(3(6x-3)*5(10x-15))), so:
35x1/(3(6x-3)*5(10x-15))
We multiply all the terms by the denominator
35x1
We add all the numbers together, and all the variables
35x
Back to the equation:
+(35x)
We calculate terms in parentheses: +(-18x6/(3(6x-3)*5(10x-15))), so:
-18x6/(3(6x-3)*5(10x-15))
We multiply all the terms by the denominator
-18x6
We add all the numbers together, and all the variables
-18x^6
We do not support expression: x^6
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