7/3(6x-3)=6/5(10x-15)

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Solution for 7/3(6x-3)=6/5(10x-15) equation: 



7/3(6x-3)=6/5(10x-15)

We move all terms to the left:

7/3(6x-3)-(6/5(10x-15))=0



Domain of the equation: 3(6x-3)!=0

x∈R





Domain of the equation: 5(10x-15))!=0

x∈R



We calculate fractions


(35x1/(3(6x-3)*5(10x-15)))+(-18x6/(3(6x-3)*5(10x-15)))=0



We calculate terms in parentheses: +(35x1/(3(6x-3)*5(10x-15))), so:

35x1/(3(6x-3)*5(10x-15))

We multiply all the terms by the denominator


35x1

We add all the numbers together, and all the variables

35x

Back to the equation:

+(35x)





We calculate terms in parentheses: +(-18x6/(3(6x-3)*5(10x-15))), so:

-18x6/(3(6x-3)*5(10x-15))

We multiply all the terms by the denominator


-18x6

We add all the numbers together, and all the variables

-18x^6

We do not support expression: x^6

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