7/3(8-n)=21(n+2)

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Solution for 7/3(8-n)=21(n+2) equation: 



7/3(8-n)=21(n+2)

We move all terms to the left:

7/3(8-n)-(21(n+2))=0



Domain of the equation: 3(8-n)!=0

n∈R



We add all the numbers together, and all the variables

7/3(-1n+8)-(21(n+2))=0

We multiply all the terms by the denominator


-((21(n+2)))*3(-1n+8)+7=0



We calculate terms in parentheses: -((21(n+2)))*3(-1n+8), so:

(21(n+2)))*3(-1n+8

We add all the numbers together, and all the variables

-1n+(21(n+2)))*3(+8

Back to the equation:

-(-1n+(21(n+2)))*3(+8)



We add all the numbers together, and all the variables

-(-1n+(21(n+2)))*38+7=0

We move all terms containing n to the left, all other terms to the right

-(-1n+(21(n+2)))*38=-7

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