7/3(c+3)=1/3-c

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Solution for 7/3(c+3)=1/3-c equation: 



7/3(c+3)=1/3-c

We move all terms to the left:

7/3(c+3)-(1/3-c)=0



Domain of the equation: 3(c+3)!=0

c∈R





Domain of the equation: 3-c)!=0

We move all terms containing c to the left, all other terms to the right

-c)!=-3

c!=-3/1

c!=-3

c∈R



We add all the numbers together, and all the variables

7/3(c+3)-(-1c+1/3)=0

We get rid of parentheses

7/3(c+3)+1c-1/3=0

We calculate fractions


c=0

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