7/3(d-2)=3/5(d+2)

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Solution for 7/3(d-2)=3/5(d+2) equation: 



7/3(d-2)=3/5(d+2)

We move all terms to the left:

7/3(d-2)-(3/5(d+2))=0



Domain of the equation: 3(d-2)!=0

d∈R





Domain of the equation: 5(d+2))!=0

d∈R



We calculate fractions


(35dd/(3(d-2)*5(d+2)))+(-9dd/(3(d-2)*5(d+2)))=0



We calculate terms in parentheses: +(35dd/(3(d-2)*5(d+2))), so:

35dd/(3(d-2)*5(d+2))

We multiply all the terms by the denominator


35dd

Back to the equation:

+(35dd)





We calculate terms in parentheses: +(-9dd/(3(d-2)*5(d+2))), so:

-9dd/(3(d-2)*5(d+2))

We multiply all the terms by the denominator


-9dd

Back to the equation:

+(-9dd)



We get rid of parentheses

35dd-9dd=0

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