7/3+1/3y=3-3y

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Solution for 7/3+1/3y=3-3y equation:



7/3+1/3y=3-3y
We move all terms to the left:
7/3+1/3y-(3-3y)=0
Domain of the equation: 3y!=0
y!=0/3
y!=0
y∈R
We add all the numbers together, and all the variables
1/3y-(-3y+3)+7/3=0
We get rid of parentheses
1/3y+3y-3+7/3=0
We calculate fractions
3y-3=0
We move all terms containing y to the left, all other terms to the right
3y=3
y=3/3
y=1

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