7/3+103/y=3y-4

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Solution for 7/3+103/y=3y-4 equation:


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

103/y+7/3 = 3*y-4 // - 3*y-4

103/y-(3*y)+7/3+4 = 0

103/y-3*y+7/3+4 = 0

103*y^-1-3*y^1+19/3*y^0 = 0

(19/3*y^1-3*y^2+103*y^0)/(y^1) = 0 // * y^2

y^1*(19/3*y^1-3*y^2+103*y^0) = 0

y^1

(19/3)*y-3*y^2+103 = 0

(19/3)*y-3*y^2+103 = 0

DELTA = (19/3)^2-(-3*4*103)

DELTA = 11485/9

DELTA > 0

y = ((11485/9)^(1/2)-(19/3))/(-3*2) or y = (-(19/3)-(11485/9)^(1/2))/(-3*2)

y = ((11485/9)^(1/2)-19/3)/(-6) or y = ((11485/9)^(1/2)+19/3)/6

y in { ((11485/9)^(1/2)-19/3)/(-6), ((11485/9)^(1/2)+19/3)/6}

y in { ((11485/9)^(1/2)-19/3)/(-6), ((11485/9)^(1/2)+19/3)/6 }

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