7/3-(2(x-10))/3=(3(x-4))/5

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Solution for 7/3-(2(x-10))/3=(3(x-4))/5 equation: 


x in (-oo:+oo)

7/3-((2*(x-10))/3) = (3*(x-4))/5 // - (3*(x-4))/5

7/3-((2*(x-10))/3)-((3*(x-4))/5) = 0

(-2/3)*(x-10)+(-3/5)*(x-4)+7/3 = 0

7/3-2/3*(x-10)-3/5*(x-4) = 0

(-2/3*3*(x-10))/3+(-3/5*3*(x-4))/3+7/3 = 0

7-2/3*3*(x-10)-3/5*3*(x-4) = 0

7-19/5*x+136/5 = 0

171/5-19/5*x = 0

(171/5-19/5*x)/3 = 0

(171/5-19/5*x)/3 = 0 // * 3

171/5-19/5*x = 0

171/5-19/5*x = 0 // - 171/5

-19/5*x = -171/5 // : -19/5

x = -171/5/(-19/5)

x = 9

x = 9

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