7/3-1/4z=72/3z

Solution for 7/3-1/4z=72/3z equation:

7/3-1/4z=72/3z

We move all terms to the left:

7/3-1/4z-(72/3z)=0


Domain of the equation: 4z!=0

z!=0/4

z!=0

z∈R



Domain of the equation: 3z)!=0

z!=0/1

z!=0

z∈R


We add all the numbers together, and all the variables

-1/4z-(+72/3z)+7/3=0

We get rid of parentheses

-1/4z-72/3z+7/3=0

We calculate fractions


(-27z)/108z^2+(-288z)/108z^2+28z/108z^2=0

We multiply all the terms by the denominator


(-27z)+(-288z)+28z=0

We add all the numbers together, and all the variables

28z+(-27z)+(-288z)=0

We get rid of parentheses

28z-27z-288z=0

We add all the numbers together, and all the variables

-287z=0

z=0/-287

z=0

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