7/3-2(x-10)/3=3(x-4)/5

Solution for 7/3-2(x-10)/3=3(x-4)/5 equation:

7/3-2(x-10)/3=3(x-4)/5

We move all terms to the left:

7/3-2(x-10)/3-(3(x-4)/5)=0

We calculate fractions


(-2x+20)/()+(-(3(x-4)*3)/()=0


We calculate terms in parentheses: +(-(3(x-4)*3)/(), so:

-(3(x-4)*3)/(

We multiply all the terms by the denominator


-(3(x-4)*3)


We calculate terms in parentheses: -(3(x-4)*3), so:

3(x-4)*3

We multiply parentheses

9x-36

Back to the equation:

-(9x-36)


We get rid of parentheses

-9x+36

Back to the equation:

+(-9x+36)


We get rid of parentheses

(-2x+20)/()-9x+36=0

We multiply all the terms by the denominator


(-2x+20)-9x*()+36*()=0

We add all the numbers together, and all the variables

(-2x+20)-9x*()=0

We get rid of parentheses

-2x-9x*()+20=0

We move all terms containing x to the left, all other terms to the right

-2x-9x*()=-20