7/3=2x+5/x

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Solution for 7/3=2x+5/x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

7/3 = 2*x+5/x // - 2*x+5/x

7/3-(2*x)-(5/x) = 0

7/3-2*x-5*x^-1 = 0

7/3*x^0-2*x^1-5*x^-1 = 0

(7/3*x^1-2*x^2-5*x^0)/(x^1) = 0 // * x^2

x^1*(7/3*x^1-2*x^2-5*x^0) = 0

x^1

(7/3)*x-2*x^2-5 = 0

(7/3)*x-2*x^2-5 = 0

DELTA = (7/3)^2-(-5*(-2)*4)

DELTA = -311/9

DELTA < 0

x in { } 

x belongs to the empty set

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