7/3=4k/2k+3

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Solution for 7/3=4k/2k+3 equation: 



7/3=4k/2k+3

We move all terms to the left:

7/3-(4k/2k+3)=0



Domain of the equation: 2k+3)!=0

k∈R



We get rid of parentheses

-4k/2k-3+7/3=0

We calculate fractions


(-12k)/6k+14k/6k-3=0

We multiply all the terms by the denominator


(-12k)+14k-3*6k=0

We add all the numbers together, and all the variables

14k+(-12k)-3*6k=0

Wy multiply elements

14k+(-12k)-18k=0

We get rid of parentheses

14k-12k-18k=0

We add all the numbers together, and all the variables

-16k=0

k=0/-16

k=0

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