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7/3m+3=5m
We move all terms to the left:
7/3m+3-(5m)=0
Domain of the equation: 3m!=0We add all the numbers together, and all the variables
m!=0/3
m!=0
m∈R
-5m+7/3m+3=0
We multiply all the terms by the denominator
-5m*3m+3*3m+7=0
Wy multiply elements
-15m^2+9m+7=0
a = -15; b = 9; c = +7;
Δ = b2-4ac
Δ = 92-4·(-15)·7
Δ = 501
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{501}}{2*-15}=\frac{-9-\sqrt{501}}{-30} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{501}}{2*-15}=\frac{-9+\sqrt{501}}{-30} $
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