7/3m+7/4m=-49/6

Solution for 7/3m+7/4m=-49/6 equation:

7/3m+7/4m=-49/6

We move all terms to the left:

7/3m+7/4m-(-49/6)=0


Domain of the equation: 3m!=0

m!=0/3

m!=0

m∈R



Domain of the equation: 4m!=0

m!=0/4

m!=0

m∈R


We get rid of parentheses

7/3m+7/4m+49/6=0

We calculate fractions


2352m^2/432m^2+1008m/432m^2+756m/432m^2=0

We multiply all the terms by the denominator


2352m^2+1008m+756m=0

We add all the numbers together, and all the variables

2352m^2+1764m=0

a = 2352; b = 1764; c = 0;
Δ = b2-4ac
Δ = 17642-4·2352·0
Δ = 3111696
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3111696}=1764$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1764)-1764}{2*2352}=\frac{-3528}{4704}
=-3/4
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1764)+1764}{2*2352}=\frac{0}{4704}
=0
$