7/3q+4=16

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Solution for 7/3q+4=16 equation: 



7/3q+4=16

We move all terms to the left:

7/3q+4-(16)=0



Domain of the equation: 3q!=0

q!=0/3

q!=0

q∈R



We add all the numbers together, and all the variables

7/3q-12=0

We multiply all the terms by the denominator


-12*3q+7=0

Wy multiply elements

-36q+7=0

We move all terms containing q to the left, all other terms to the right

-36q=-7

q=-7/-36

q=7/36

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