7/3t2=19+5t

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Solution for 7/3t2=19+5t equation: 


t in (-oo:+oo)

(7/3)*t^2 = 5*t+19 // - 5*t+19

(7/3)*t^2-(5*t)-19 = 0

(7/3)*t^2-5*t-19 = 0

7/3*t^2-5*t-19 = 0

DELTA = (-5)^2-(-19*7/3*4)

DELTA = 607/3

DELTA > 0

t = ((607/3)^(1/2)+5)/(2*7/3) or t = (5-(607/3)^(1/2))/(2*7/3)

t = 3/14*((607/3)^(1/2)+5) or t = 3/14*(5-(607/3)^(1/2))

t in { 3/14*(5-(607/3)^(1/2)), 3/14*((607/3)^(1/2)+5) }

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