7/3u=35

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Solution for 7/3u=35 equation:



7/3u=35
We move all terms to the left:
7/3u-(35)=0
Domain of the equation: 3u!=0
u!=0/3
u!=0
u∈R
We multiply all the terms by the denominator
-35*3u+7=0
Wy multiply elements
-105u+7=0
We move all terms containing u to the left, all other terms to the right
-105u=-7
u=-7/-105
u=1/15

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