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7/3x+1/3x=12+5/3x
We move all terms to the left:
7/3x+1/3x-(12+5/3x)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
7/3x+1/3x-(5/3x+12)=0
We get rid of parentheses
7/3x+1/3x-5/3x-12=0
We multiply all the terms by the denominator
-12*3x+7+1-5=0
We add all the numbers together, and all the variables
-12*3x+3=0
Wy multiply elements
-36x+3=0
We move all terms containing x to the left, all other terms to the right
-36x=-3
x=-3/-36
x=1/12
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