7/3x+2-3/2x=5

Solution for 7/3x+2-3/2x=5 equation:

7/3x+2-3/2x=5

We move all terms to the left:

7/3x+2-3/2x-(5)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We add all the numbers together, and all the variables

7/3x-3/2x-3=0

We calculate fractions


14x/6x^2+(-9x)/6x^2-3=0

We multiply all the terms by the denominator


14x+(-9x)-3*6x^2=0

Wy multiply elements

-18x^2+14x+(-9x)=0

We get rid of parentheses

-18x^2+14x-9x=0

We add all the numbers together, and all the variables

-18x^2+5x=0

a = -18; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·(-18)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*-18}=\frac{-10}{-36}
=5/18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*-18}=\frac{0}{-36}
=0
$