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7/3x+8=5x
We move all terms to the left:
7/3x+8-(5x)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
-5x+7/3x+8=0
We multiply all the terms by the denominator
-5x*3x+8*3x+7=0
Wy multiply elements
-15x^2+24x+7=0
a = -15; b = 24; c = +7;
Δ = b2-4ac
Δ = 242-4·(-15)·7
Δ = 996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{996}=\sqrt{4*249}=\sqrt{4}*\sqrt{249}=2\sqrt{249}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-2\sqrt{249}}{2*-15}=\frac{-24-2\sqrt{249}}{-30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+2\sqrt{249}}{2*-15}=\frac{-24+2\sqrt{249}}{-30} $
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