7/3z+8/z-4

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Solution for 7/3z+8/z-4 equation: 


D( z )

z = 0

z = 0

z = 0

z in (-oo:0) U (0:+oo)

(7/3)*z+8/z-4 = 0

7/3*z^1+8*z^-1-4*z^0 = 0

(7/3*z^2-4*z^1+8*z^0)/(z^1) = 0 // * z^2

z^1*(7/3*z^2-4*z^1+8*z^0) = 0

z^1

(7/3)*z^2-4*z+8 = 0

(7/3)*z^2-4*z+8 = 0

DELTA = (-4)^2-(4*8*(7/3))

DELTA = -176/3

DELTA < 0

z in { } 

z belongs to the empty set

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