7/4(x+3)=2

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Solution for 7/4(x+3)=2 equation: 



7/4(x+3)=2

We move all terms to the left:

7/4(x+3)-(2)=0



Domain of the equation: 4(x+3)!=0

x∈R



We multiply all the terms by the denominator


-2*4(x+3)+7=0

Wy multiply elements

-8x(x+7=0

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