7/4=x-3/x+4

Solution for 7/4=x-3/x+4 equation:

D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

7/4 = x-(3/x)+4 // - x-(3/x)+4

3/x-x+7/4-4 = 0

3*x^-1-1*x^1-9/4*x^0 = 0

(3*x^0-1*x^2-9/4*x^1)/(x^1) = 0 // * x^2

x^1*(3*x^0-1*x^2-9/4*x^1) = 0

x^1

(-9/4)*x-x^2+3 = 0

(-9/4)*x-x^2+3 = 0

DELTA = (-9/4)^2-(-1*3*4)

DELTA = 273/16

DELTA > 0

x = ((273/16)^(1/2)-(-9/4))/(-1*2) or x = (-(-9/4)-(273/16)^(1/2))/(-1*2)

x = ((273/16)^(1/2)+9/4)/(-2) or x = (9/4-(273/16)^(1/2))/(-2)

x in { ((273/16)^(1/2)+9/4)/(-2), (9/4-(273/16)^(1/2))/(-2)} 

x in { ((273/16)^(1/2)+9/4)/(-2), (9/4-(273/16)^(1/2))/(-2) }