7/4x+1=6/x-5

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Solution for 7/4x+1=6/x-5 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(7/4)*x+1 = 6/x-5 // - 6/x-5

(7/4)*x-(6/x)+1+5 = 0

(7/4)*x-6*x^-1+1+5 = 0

7/4*x^1-6*x^-1+6*x^0 = 0

(7/4*x^2+6*x^1-6*x^0)/(x^1) = 0 // * x^2

x^1*(7/4*x^2+6*x^1-6*x^0) = 0

x^1

(7/4)*x^2+6*x-6 = 0

(7/4)*x^2+6*x-6 = 0

DELTA = 6^2-(-6*4*(7/4))

DELTA = 78

DELTA > 0

x = (78^(1/2)-6)/(2*(7/4)) or x = (-78^(1/2)-6)/(2*(7/4))

x = 2/7*(78^(1/2)-6) or x = -2/7*(78^(1/2)+6)

x in { -2/7*(78^(1/2)+6), 2/7*(78^(1/2)-6)}

x in { -2/7*(78^(1/2)+6), 2/7*(78^(1/2)-6) }

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