7/5(-2x-3)=8

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Solution for 7/5(-2x-3)=8 equation:



7/5(-2x-3)=8
We move all terms to the left:
7/5(-2x-3)-(8)=0
Domain of the equation: 5(-2x-3)!=0
x∈R
We multiply all the terms by the denominator
-8*5(-2x-3)+7=0
Wy multiply elements
-40x(-+7=0
We use the square of the difference formula
-40x(-7=0

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