7/5(15x-20)=1/3(12x-9)

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Solution for 7/5(15x-20)=1/3(12x-9) equation: 



7/5(15x-20)=1/3(12x-9)

We move all terms to the left:

7/5(15x-20)-(1/3(12x-9))=0



Domain of the equation: 5(15x-20)!=0

x∈R





Domain of the equation: 3(12x-9))!=0

x∈R



We calculate fractions


(21x1/(5(15x-20)*3(12x-9)))+(-5x1/(5(15x-20)*3(12x-9)))=0



We calculate terms in parentheses: +(21x1/(5(15x-20)*3(12x-9))), so:

21x1/(5(15x-20)*3(12x-9))

We multiply all the terms by the denominator


21x1

We add all the numbers together, and all the variables

21x

Back to the equation:

+(21x)





We calculate terms in parentheses: +(-5x1/(5(15x-20)*3(12x-9))), so:

-5x1/(5(15x-20)*3(12x-9))

We multiply all the terms by the denominator


-5x1

We add all the numbers together, and all the variables

-5x

Back to the equation:

+(-5x)



We get rid of parentheses

21x-5x=0

We add all the numbers together, and all the variables

16x=0

x=0/16

x=0

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