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7/5-(5x-3)=1/5x-12
We move all terms to the left:
7/5-(5x-3)-(1/5x-12)=0
Domain of the equation: 5x-12)!=0We get rid of parentheses
x∈R
-5x-1/5x+3+12+7/5=0
We calculate fractions
-5x+3+12=0
We add all the numbers together, and all the variables
-5x+15=0
We move all terms containing x to the left, all other terms to the right
-5x=-15
x=-15/-5
x=+3
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