7/5v+3/2v=1

Solution for 7/5v+3/2v=1 equation:

7/5v+3/2v=1

We move all terms to the left:

7/5v+3/2v-(1)=0


Domain of the equation: 5v!=0

v!=0/5

v!=0

v∈R



Domain of the equation: 2v!=0

v!=0/2

v!=0

v∈R


We calculate fractions


14v/10v^2+15v/10v^2-1=0

We multiply all the terms by the denominator


14v+15v-1*10v^2=0

We add all the numbers together, and all the variables

29v-1*10v^2=0

Wy multiply elements

-10v^2+29v=0

a = -10; b = 29; c = 0;
Δ = b2-4ac
Δ = 292-4·(-10)·0
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-29}{2*-10}=\frac{-58}{-20}
=2+9/10
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+29}{2*-10}=\frac{0}{-20}
=0
$