7/5x+3/x=4/x-4

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Solution for 7/5x+3/x=4/x-4 equation: 



7/5x+3/x=4/x-4

We move all terms to the left:

7/5x+3/x-(4/x-4)=0



Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R





Domain of the equation: x!=0

x∈R





Domain of the equation: x-4)!=0

x∈R



We get rid of parentheses

7/5x+3/x-4/x+4=0

We calculate fractions


7x/5x^2+(-20x+3)/5x^2+4=0

We multiply all the terms by the denominator


7x+(-20x+3)+4*5x^2=0

Wy multiply elements

20x^2+7x+(-20x+3)=0

We get rid of parentheses

20x^2+7x-20x+3=0

We add all the numbers together, and all the variables

20x^2-13x+3=0

a = 20; b = -13; c = +3;
Δ = b2-4ac
Δ = -132-4·20·3
Δ = -71
Delta is less than zero, so there is no solution for the equation

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