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7/5x+3x=15
We move all terms to the left:
7/5x+3x-(15)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
3x+7/5x-15=0
We multiply all the terms by the denominator
3x*5x-15*5x+7=0
Wy multiply elements
15x^2-75x+7=0
a = 15; b = -75; c = +7;
Δ = b2-4ac
Δ = -752-4·15·7
Δ = 5205
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-75)-\sqrt{5205}}{2*15}=\frac{75-\sqrt{5205}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-75)+\sqrt{5205}}{2*15}=\frac{75+\sqrt{5205}}{30} $
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