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7/5x-2x=-3
We move all terms to the left:
7/5x-2x-(-3)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
-2x+7/5x+3=0
We multiply all the terms by the denominator
-2x*5x+3*5x+7=0
Wy multiply elements
-10x^2+15x+7=0
a = -10; b = 15; c = +7;
Δ = b2-4ac
Δ = 152-4·(-10)·7
Δ = 505
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{505}}{2*-10}=\frac{-15-\sqrt{505}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{505}}{2*-10}=\frac{-15+\sqrt{505}}{-20} $
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