7/5x=40

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Solution for 7/5x=40 equation: 



7/5x=40

We move all terms to the left:

7/5x-(40)=0



Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



We multiply all the terms by the denominator


-40*5x+7=0

Wy multiply elements

-200x+7=0

We move all terms containing x to the left, all other terms to the right

-200x=-7

x=-7/-200

x=7/200

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