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7/5x=5+2/5x
We move all terms to the left:
7/5x-(5+2/5x)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
7/5x-(2/5x+5)=0
We get rid of parentheses
7/5x-2/5x-5=0
We multiply all the terms by the denominator
-5*5x+7-2=0
We add all the numbers together, and all the variables
-5*5x+5=0
Wy multiply elements
-25x+5=0
We move all terms containing x to the left, all other terms to the right
-25x=-5
x=-5/-25
x=1/5
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