7/6(3x-1)-81/3=3/2(2x-5)

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Solution for 7/6(3x-1)-81/3=3/2(2x-5) equation: 



7/6(3x-1)-81/3=3/2(2x-5)

We move all terms to the left:

7/6(3x-1)-81/3-(3/2(2x-5))=0



Domain of the equation: 6(3x-1)!=0

x∈R





Domain of the equation: 2(2x-5))!=0

x∈R



We add all the numbers together, and all the variables

7/6(3x-1)-(3/2(2x-5))-27=0

We calculate fractions


(14x2/(6(3x-1)*2(2x-5)))+(-18x3/(6(3x-1)*2(2x-5)))-27=0



We calculate terms in parentheses: +(14x2/(6(3x-1)*2(2x-5))), so:

14x2/(6(3x-1)*2(2x-5))

We multiply all the terms by the denominator


14x2

We add all the numbers together, and all the variables

14x^2

Back to the equation:

+(14x^2)





We calculate terms in parentheses: +(-18x3/(6(3x-1)*2(2x-5))), so:

-18x3/(6(3x-1)*2(2x-5))

We multiply all the terms by the denominator


-18x3

We add all the numbers together, and all the variables

-18x^3

We do not support expression: x^3

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