7/6-2/3x=4/x

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Solution for 7/6-2/3x=4/x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

7/6-((2/3)*x) = 4/x // - 4/x

7/6-((2/3)*x)-(4/x) = 0

(-2/3)*x-4*x^-1+7/6 = 0

7/6*x^0-2/3*x^1-4*x^-1 = 0

(7/6*x^1-2/3*x^2-4*x^0)/(x^1) = 0 // * x^2

x^1*(7/6*x^1-2/3*x^2-4*x^0) = 0

x^1

(-2/3)*x^2+(7/6)*x-4 = 0

(-2/3)*x^2+(7/6)*x-4 = 0

DELTA = (7/6)^2-(-4*4*(-2/3))

DELTA = -335/36

DELTA < 0

x in { } 

x belongs to the empty set

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