7/6=2(-g)/3

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Solution for 7/6=2(-g)/3 equation: 



7/6=2(-g)/3

We move all terms to the left:

7/6-(2(-g)/3)=0

We add all the numbers together, and all the variables

-(2(-1g)/3)+7/6=0

We calculate fractions


(-(2(-1g)*6)/()+()/()=0



We calculate terms in parentheses: +(-(2(-1g)*6)/()+()/(), so:

-(2(-1g)*6)/()+()/(

We add all the numbers together, and all the variables

-(2(-1g)*6)/()+1

We multiply all the terms by the denominator


-(2(-1g)*6)+1*()



We calculate terms in parentheses: -(2(-1g)*6), so:

2(-1g)*6

We multiply parentheses

-12g

Back to the equation:

-(-12g)



We add all the numbers together, and all the variables

-(-12g)

We get rid of parentheses

12g

Back to the equation:

+(12g)



g=0/12

g=0

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