7/8(-32-48x)+36=2/3(-33x-18)-10

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Solution for 7/8(-32-48x)+36=2/3(-33x-18)-10 equation: 



7/8(-32-48x)+36=2/3(-33x-18)-10

We move all terms to the left:

7/8(-32-48x)+36-(2/3(-33x-18)-10)=0



Domain of the equation: 8(-32-48x)!=0

x∈R





Domain of the equation: 3(-33x-18)-10)!=0

x∈R



We add all the numbers together, and all the variables

7/8(-48x-32)-(2/3(-33x-18)-10)+36=0

We calculate fractions


(21x(-)/(8(-48x-32)*3(-33x-18))+(-16x0/(8(-48x-32)*3(-33x-18))+36=0

We can not solve this equation

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