7/8(-3y+1)=-2y-1

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Solution for 7/8(-3y+1)=-2y-1 equation: 



7/8(-3y+1)=-2y-1

We move all terms to the left:

7/8(-3y+1)-(-2y-1)=0



Domain of the equation: 8(-3y+1)!=0

y∈R



We get rid of parentheses

7/8(-3y+1)+2y+1=0

We multiply all the terms by the denominator


2y*8(-3y+1)+1*8(-3y+1)+7=0

Wy multiply elements

16y^2(-+8y(-+7=0

We use the square of the difference formula

16y^2(-8y(-7=0

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