7/8b-32=6/8b+32

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Solution for 7/8b-32=6/8b+32 equation: 



7/8b-32=6/8b+32

We move all terms to the left:

7/8b-32-(6/8b+32)=0



Domain of the equation: 8b!=0

b!=0/8

b!=0

b∈R





Domain of the equation: 8b+32)!=0

b∈R



We get rid of parentheses

7/8b-6/8b-32-32=0

We multiply all the terms by the denominator


-32*8b-32*8b+7-6=0

We add all the numbers together, and all the variables

-32*8b-32*8b+1=0

Wy multiply elements

-256b-256b+1=0

We add all the numbers together, and all the variables

-512b+1=0

We move all terms containing b to the left, all other terms to the right

-512b=-1

b=-1/-512

b=1/512

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