7/8m-1/2=3/16m+5

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Solution for 7/8m-1/2=3/16m+5 equation:



7/8m-1/2=3/16m+5
We move all terms to the left:
7/8m-1/2-(3/16m+5)=0
Domain of the equation: 8m!=0
m!=0/8
m!=0
m∈R
Domain of the equation: 16m+5)!=0
m∈R
We get rid of parentheses
7/8m-3/16m-5-1/2=0
We calculate fractions
(-128m^2)/512m^2+448m/512m^2+(-96m)/512m^2-5=0
We multiply all the terms by the denominator
(-128m^2)+448m+(-96m)-5*512m^2=0
Wy multiply elements
(-128m^2)-2560m^2+448m+(-96m)=0
We get rid of parentheses
-128m^2-2560m^2+448m-96m=0
We add all the numbers together, and all the variables
-2688m^2+352m=0
a = -2688; b = 352; c = 0;
Δ = b2-4ac
Δ = 3522-4·(-2688)·0
Δ = 123904
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{123904}=352$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(352)-352}{2*-2688}=\frac{-704}{-5376} =11/84 $
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(352)+352}{2*-2688}=\frac{0}{-5376} =0 $

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