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7/8m-2=m
We move all terms to the left:
7/8m-2-(m)=0
Domain of the equation: 8m!=0We add all the numbers together, and all the variables
m!=0/8
m!=0
m∈R
-1m+7/8m-2=0
We multiply all the terms by the denominator
-1m*8m-2*8m+7=0
Wy multiply elements
-8m^2-16m+7=0
a = -8; b = -16; c = +7;
Δ = b2-4ac
Δ = -162-4·(-8)·7
Δ = 480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{480}=\sqrt{16*30}=\sqrt{16}*\sqrt{30}=4\sqrt{30}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-4\sqrt{30}}{2*-8}=\frac{16-4\sqrt{30}}{-16} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+4\sqrt{30}}{2*-8}=\frac{16+4\sqrt{30}}{-16} $
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