7/8x+2=1-3/4x

Solution for 7/8x+2=1-3/4x equation:

7/8x+2=1-3/4x

We move all terms to the left:

7/8x+2-(1-3/4x)=0


Domain of the equation: 8x!=0

x!=0/8

x!=0

x∈R



Domain of the equation: 4x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

7/8x-(-3/4x+1)+2=0

We get rid of parentheses

7/8x+3/4x-1+2=0

We calculate fractions


28x/32x^2+24x/32x^2-1+2=0

We add all the numbers together, and all the variables

28x/32x^2+24x/32x^2+1=0

We multiply all the terms by the denominator


28x+24x+1*32x^2=0

We add all the numbers together, and all the variables

52x+1*32x^2=0

Wy multiply elements

32x^2+52x=0

a = 32; b = 52; c = 0;
Δ = b2-4ac
Δ = 522-4·32·0
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(52)-52}{2*32}=\frac{-104}{64}
=-1+5/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(52)+52}{2*32}=\frac{0}{64}
=0
$